Math, asked by sudha541rani, 11 days ago

2. Find two numbers such that their sum is 27056 and difference 846.
3. The sum of two numbers is 2157 and one of them is twice the other. Find them
4. A number is thrice another number and their sum is 4816, find the two numbers.
them is half of the other. Find the​

Answers

Answered by AghilaCC
1

Answer:

2) Numbers = 13951, 13105

3) Numbers = 719, 1438

4) Numbers = 1204, 3612

The last question is not clear

Step-by-step explanation:

2) Let the numbers be x and y.

x + y = 27056

x - y = 846

(x + y) + (x - y) = 27056 + 846

2x = 27902

x = 27902 ÷ 2 = 13951

Substituting the value of x in x + y = 27056 we get

13951 + y = 27056

y = 27056 - 13951 = 13105

3) x + y = 2157

y is 2 times x. ie, y = 2x

Substituting this in x + y = 2157 we get

x + 2x = 2157

3x = 2157

x = 2157 ÷ 3 = 719

Substituting the value of x in x + y = 2157 we get

719 + y = 2157

y = 2157 - 719 = 1438

4) x + y = 4816

y is three times x. ie, y = 3x

Substituting this in x + y = 4816 we get

x + 3x = 4816

4x = 4816

x = 4816 ÷ 4 = 1204

Substituting this in x + y = 4816 we get

1204 + y = 4816

y = 4816 - 1204 = 3612

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