2. Find two such least consecutive numbers so that the difference of
squares of them is a perfect square number.
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The square root of the differences of their squares is 2N+1. If you accept “0” then the least pair of consecutive numbers is 0 & 1. ... As pointed out in another answer, these sets of three numbers (4, 5 & 3, . . 112, 113 & 15, . . . )
hope it helps....
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