Question

(2) For an A.P. 6.4.2 find S10​

Answer 1

Answer:

S10 = 10/2 [2×6+ (10-1)-2]

=> S10= 5[ 12 -18]

=>S10 = -30

Answer 2

Explanation:

USING GERNAL FORMULA OF SUM : Sn = 2a + (n-1) d

Sn = 2a+(n-1)d

Sn = 2(6) +(10-1) -2

Sn = 12+ (-18)

Sn = -30

S10 = -30

THIS IS YOUR ANSWER MAY U UNDERSTAND . BEST OF LUCK