Question

2. For the cell, Hg, Hg, C1/C1 -(0.1M) *I/CI -
(0.01M)/C12, Pt Eºcell is 1.10 V. Hence, Ecell is
1) 1.1591 V
2) -1.1591 V
3) 1.0409 V
4) -1.0409 V​

Answer 1

Answer: The approximate right answer would be option (3)

Explanation:

Answer 2

Answer:

Explanation:

E CELL = ENOT CELL - 0.0591/N LOG Q

E CELL = 1.1 - 0.0591LOG 0.01/0.1

1.1591