Question

2. For the following circuit V source =15V, R1=25Ω, and V2=5.6V . What is the value of R2?

Answer 1

Answer:

R=6+3=9Ω

V=4V

I=RV=94=0.45A

(ii) 12 ohm and 3 ohm are in series

R=12+3=15Ω

I=RV=154=0.27A

p.d across 12 ohms= IR=0.27×12=3.24V