Question

2.
For the reaction PCI 5 PCI,(9) + Cl (9)
The moles of each component PCI, PCI, and Cl,
at equilibrium were found to be 2. If the total
pressure is 3 atm. The K will be (standard state
= 1 atm]
(A) 1
(B) 2
(C) 3
(D) 1.5​

Answer 1

1 atm

Total pressure is 3 atm.

Total number of moles =2+2+2=6

Number of moles of PCl

5

=2

Mole fraction of PCl

5

=

6

2

=0.333

Partial pressure of PCl

5

=0.333×3 atm=1 atm.

Number of moles of PCl

3

=2

Mole fraction of PCl

3

=

6

2

=0.333

Partial pressure of PCl

3

=0.333×3 atm=1 atm.

Number of moles of Cl

2

=2

Mole fraction of Cl

2

=

6

2

=0.333

Partial pressure of Cl

2

=0.333×3 atm=1 atm.

The equilibrium constant K

p

=

P

PCl5

P

PCl3

×P

Cl2

K

p

=

1

1×1

=1