2.
For two resistors R, and R2, connected in
parallel, the relative error in their equivalent
resistance is (Where R = (10.0 + 0.1) 2 and
R2 = (20.0 +0.4) 2)
[NCERT Pg. 27]
(2) 0.05
(1) 0.08
(3) 0.01
(4) 0.04
but the answer is(3)0.01 can any one explain plz
Answers
Answered by
0
Answer:
not understand m.......
Answered by
2
Answer:
2)0.08 is the correct answer
Pls mark me brainlist
Similar questions