Question

2. For
what
value of k,
,–3 is a zero of the polynomial
X2 + 11x+ k ?
​

Answer 1

Answer:

Simply put -3 in equation and equate to zero.

Step-by-step explanation:

${x}^{2} + 11x + k = 0 \\ {( - 3)}^{2} + 11( - 3) + k = 0 \\ 9 - 33 +k = 0 \\ k = 33 - 9 \\ k = 24$

Answer 2

Answer:

Given the polynomial

x^2+11x+k x=-3

then

(-3) ^2+11(-3)+k

9-33+k

-24+k

so if k=24

then -24+24=0

if k equal to 24 then given polynomial is zero