Question

2. From the following figure, find the values of :
(i) cos B
(ii) tan C
(iii) sin?B + cos2B
(iv) sin B.cos C + cos B.sin
A
8.
С
B
17​

Answer 1

Answer:

cos B = √1-sin^2B

tanC = sinC/cosC

sin2 B+ cos2B

sinB.CosC.+ cosB.sinC

Answer 2

I low-key love Trigonometry , so here you go....I found the figure from the Selina Text that i bought from the library for my studies in 11 grade .. I hope it's from that text ..

Now Here You GO ,

1. cos B

adjacent / hypotenuse = 8/17

2. tan C

opposite / adjacent = 8 / ?

=BC^2 = AB^2+AC^2

= 17^2=862+AC^2

=289-64=AC^2

=225=AC^2

$\sqrt{225}$=AC

AC=15

therefore tan C=8/15

3.sin^2B + cos^2B

sin^2B = (15/17)^2

sin^2B = 225/289

cos^2B = (8/17)^2

cos^2B = 64/289

sin^2B + cos^2B = (225+64)/289

                           = 289/289 = 1

4.sin B.cos C + cos B.sin

=15/17 * 15/17 + 8/17 * 8/17

=225/289 + 64/289

=1