Question

2. From the following molar conductivities at infinite dilution,
Anfor Ba(OH)2=457.6 Cm mole
A for BaCl2 =240.6 0 Cm mole
for NH di =129.8 o'cm mole?
Calculate om for NH,OH,​

Answer 1

Answer:

student-nameGeetha answered this

in Chemistry, Class

The formation of BaCl2 is represented asBa(OH)2 +2 NH4Cl →2NH4OH + BaCl2λ∞MBa(OH)2 +2 λ∞MNH4Cl = 2 λ∞MNH4OH + λ∞MBaCl2 457.6 + 2 × 129.8 = 2 × λ∞MNH4OH + 240.62 λ∞MNH4OH =476.6λ∞MNH4OH =476.62 =238.3 ohm−1cm2mol−1

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student-nameKanishka Yadav answered this

in Chemistry, Class XII-Science

limiting molar conductivity for NH4OH =LMC for (NH4^+) +(OH^-)

ADDING bacl2 in the solution

now limiting molar conductivity [ NH4CL+1/2 Ba(OH)2 -Bacl2]