Question

2. From the top of a cliff, 50 m high, the angle of depression of a buoy is 30°. Calculate to the
nearest metre, the distance of
the buoy from the foot of the cliff. [Take 13 = 1.732]

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Answer 1

Answer:86.6m

Step-by-step explanation:

Answer 2

Consider a cliff AB of 50 m (high), the angle of depression of a buoy is 30°. (Angle ACB = 30°)

We have to calculate the nearest metre, the distance of the buoy from the foot of the cliff.

To find the nearest distance of the buoy from the foot of the cliff.

Assume BC as 'x' m.

⇒ tan 30° = P/B

Here, P (perpendicular) = 50 m and B (base) = x m

Substitute these values

⇒ tan 30° = 50/x

⇒ 1/√3 = 50/x

Cross-multiply them

⇒ x = 50√3

Also given that, √3 = 1.732

⇒ x = 50(1.732)

⇒ x = 86.6 m

Therefore,

86.6 m is the distance of the buoy from the foot of the cliff.