2 g atom of A reacts with 2 g molecule of B4.
according to following reaction I limitna
2A2 (g)+3B4 (g) gives 4C
Correct statement is
(1) A2, will be the limiting reagent
(2) B4 will be the limiting reagent
(3) 2 * N, atom of C will be formed
which
(4) Both (1) & (3)
Answers
Answered by
27
It has given that, 2 g atom of A reacts with 2 g molecule of B₄ according to the following chemical reaction,
2A₂ + 3B₄ ⇒4C
We have to check which option (s) is correct.
Solution : g atom or g molecule is another name of mole.
Now it means, 2 moles of A react with 2 moles of B₄.
⇒ 4 moles of A₂ react with 2 moles of B₄.
But from chemical reaction,
2 moles of A₂ react with 3 moles of B₄.
or, 4 moles of A₂ react with 6 moles of B₄.
6 moles(required) > 2 mole (given)
So, B₄ is limiting reagent.
Now 3 moles of B₄ give 4 mole of C
So, 2 moles of B₄ give 4/3 × 2 = 2.67 moles of C.
Therefore option (B) is correct choice.
Answered by
11
Answer:
option 4 is correct.
Explanation:
see the attached file
Attachments:
Similar questions