Question

2 g of a mixture of Zn (equivalent weight 32.5) and Mg (equivalent weight 12) displace 1600 c.c. of dry hydrogen at NTP from an acid. What is the percentage composition of the mixtures​

Answer 1

Answer:

Correct option is

B

32

Given,

Mass of metal=0.32g

Volume of hydrogen=112ml

=112×10

−3

L

Now we know,

Equivalent Weight of metal is the mass of metal required to produce 1gm of Hydrogen ⟶(1)

Now, We know 1 mole of hydrogen= 22.4L of H

2

⇒ If 0.32g Metal produces 112×10

−3

L of H

2

∴ Mass of mass metal required to produce 11.2L of H

2

[∵1gmH

2

=11.2L of H

2

]=

112×10

−3

0.32×11.2

=32gm

∴ From (1) Equivalent weight of metal= 32gm