Question

2 g of mixture of CO and CO2 on reaction with excess I2O5 produced 2.54 g of I2 What would be the mass % of CO2 in the original mixture?

Answer 1

Answer:

5 CO + I2O5 ------> 5 CO2 + I2

1 mol of I2 = 1 mol of I2O5 = 5 mol of CO

Hence mol of CO = 5 * 2.54/254 = 0.05

Mass of CO = 0.05 * 28 = 1.4 gm

Mass of CO2 = 2 - 1.4 = 0.6 gm

Mass % of CO2 = 30%