Question

2. Given 20-5x <5(x + 8), find the smallest value of x when
(i) x belongs to I
(ii) x belongs to W
(iii) χbelonga to N​

Answer 1

Answer:

the x belongs to the integers

Answer 2

Solution :-

We Have

20 - 5x < 5(x + 8)

→ 20 - 5x < 5x + 40

Subtract (20 - 5x) from both sides

→ 0 < 5x + 40 - (20 - 5x)

→ 10x + 20 > 0

or

→ 10x > -20

→ x > -2

Smallest value of x

(i) When X is an integer

→ x = -1

(ii) When x is a whole number

→ x = 0

(iii) When x is a natural number

→ x = 1