2 Given the formula s = ut +1/2at power 2, where
s = distance (in metres)
u= initial velocity (in m/s)
a = acceleration (in m/s2)
t = time (in seconds)
in this question 2 the power 2 is only for t
Find the value of s when:
a) u = 500 m/s, t = 10 s and a =-4 m/s2
b) u = 300 m/s, t=5.8s and a = -25 m/s2
c) u = 1000 m/s, t = 52s and a = - 12.6 m/s2
d) u = 80 m/s, t = 5s and a = -12.5 m/s2
e) u = 0 m/s, t = 10s and a = 0 m/ss2
Answers
sorry second one is wrong
Right one is
s=ut+1/2at²
=300*5.8+1/2*-25*5.8²
=1740-420.5
=1319.5 m/s²
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Answer:
Step-by-step explanation:
a.) Given =u= 500 m/s, t= 10sec and a= -25 m/s^2
To find= distance
The acceleration is negative which means it is retarding.
Now, put all values in the formula
s= ut+ 1/2 at^2
s= 500*10+ 1/2 (-25)*(10)^2
s= 5000 + 1/2 (-25)*100
s=5000+ (-125)/2
s=5000-125/2
Cross multiplication
s=10000-125/2
s=9875/2=> 4937.5 m
b.) Given, u=300 m/s ,t=5.8 m/s and a=-25 m/s^2
To find =distance
Put all values in the formula
s=ut+1/2at^2
s=300*5.8+1/2(-25)*(5.8)^2
s=1740+1/2(-25)*33.64
s=1740+1/2(-814)
s=1740-814/2
Cross multiplication
s=3480-814/2
s=2666/2=1333m
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