Question

.2 Given two vectors, a = 4i - 3j and b = 6i + 8j, find the magnitudes and directions

(with the + x-axis) of b-a
​

Answer 1

Answer:

Vector (b-a)= (6i+8j-(4i-3j) = 2i +11j. Magnitude of vector (b-a) = √{(2)^2+(11)^2} = 5√5 units. Direction of vector (b-a) = tan^-1(11/2)from positive x-axis. Answer.