Question

2 glass plates each of length 16cm and breadth 8cm move parallel to each other in WATER with a relative velocity of 6m/s. if the viscous force is 175×10^-5, what is their distance of separation?(viscosity of water = 0.001PL)​

Answer 1

Distance of separation between two plates is 43.89 mm

Explanation:

Viscosity of water, η = 0.001 PL = 10⁻³ PL

Velocity, V = 6 m/s

Viscous force, F = 175×10⁻⁵

Length of glass plates, L = 16 cm = 16 x 10⁻² m

Breadth of glass plates, B = 8 cm = 8 x 10⁻² m

Distance of separation between two plates, l = ?

Thus, Area of  glass plates , A:

A = L x B

=  16 x 10⁻² x 8 x 10⁻²

= 128 x 10⁻⁴

According to the formula of viscosity, η:

η = Fx l / V x A

l = η x V x A/F

= 10⁻³ x 6 x 128 x 10⁻⁴ / 175 x 10⁻⁵

= 43.89 mm

Thus distance of separation between two plates is 43.89 mm.

Also learn more

A metal plate 5 cm by 5 cm rests on a layer of castor oil 1 mm thick whose coefficient of viscosity is 1.55 Nsm^-2. Calculate the magnitude of applied force. ?

https://brainly.in/question/10666901

Answer 2

Explanation:

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