Question

2 gm ice at -20°C is mixed with 1 gm steam
at 100°C in a calorimeter. When thermal
equilibrium is attained, then amount of water
in calorimeter is​

Answer 1

Answer:

2.7g

Explanation:

Heat released when 1g of steam at 100°C converts into 1g of water at 100°C=540cal

Heat required by 2g of ice at - 20°C to convert into 2g of water at 100°C=20+160+200=380

Now total amount of water is 3g at 100°C

Energy left=160cal

Mass of water at 100°C that converts into steam at 100°C=160/540=0.3g

So mass of water left=3-0.3=2.7g