Question

2 gm of metal on reaction with H2SO4 give 5 g of metal sulphate. Find equivalent mass of metal​

Answer 1

I think the answer is correct

Answer 2

Given :

Mass of the metal = 2 g

Mass of the product formed metal sulphate = 5 g

To find :

Equivalent mass of the metal

Solution :

Molar mass of sulphate ion = 32 + 16 × 4 = 96 g/mol

Valency of sulphate ion = 2

We know,

Equivalent Mass of sulphate ion

$= \frac{molar \: mass}{valency}$

$= \frac{96}{2}$

$= 48 \:$

Let the equivalent mass of the metal be ‘X' g

The equivalent mass of the metal sulphate = ( X + 48)g

When the mass of the metal is ‘X’ g, the mass of its sulphate = (X + 48) g

If the mass of metal is 2g, then the mass of sulphate

= [ 2(X + 48) /X] g

According to question,

The mass of metal sulphate produced = 5g

Then,

[ 2(X + 48) /X ] = 5g

2X + 96 = 5X

5X - 2X = 96

3X = 96

X = 96/3

X = 32 .

Thus, the required equivalent mass of the metal is 32 .