Question

2 gram mixture of o2 and o3 have a volume of 1200 ml at stp . calculate the weight of o2 in that mixtute.

Answer 1

Let mass of O2 be x.

So obviously O3 has a mass of 2-x.

We know that 22400ml is occupied by 1 mole of any gas.(AT STP)

Thus, number of moles in 1200 ml is 0.05357 moles.

This= moles of O2 + moles of O3.

=(x/32) + ((2-x)/48)=0.05357
Thus x comes out to be 1.14272gm= mass of O2

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