Question

2 gram sample of of Xenon reacts with fluorine the mass of the compound produced is 3.158 what will be the empirical formula for the compound​

Answer 1

Answer:

XeF4

Explanation:

Answer 2

Answer:

XeF4

Explanation :

Xe - 132

F- 19

Here 2g Xe react with F to produce 3.158g coumpund.

F= 3.158-2 = 1.158g.

Now let check that 2 g Xe reacts with how much fluorine,

132g Xe react with 38g of F (F2)

Then 2g Xe = 38*2/132 = 0.575g of F

which is not equal to 1.158g. Therefore XeF2 is not the answer.

next 76g of F (F4)

Then 2g of Xe = 2*76/132 = 1.151g of F

Which is equal to the given value . ie, 1.158g.

Thus answer is XeF4.