2 grams of steam condenses when passed through 40 gram of water initially at 25 degree celsius
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Here, the energy released by the condensation is used to heat the water. Even condensed water will also come to the temperature 54.3 degree from 100 degree .
Therefore, Converting Joule/gm to cal/gm we get Latent heat L = 539.43 ≈ 540 cal/gmRead more on Sarthaks.com -
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