2 guys, A and B are standing at the same point X at 5:00 PM. A walks at 5KM/HR, B is on a cycle and goes at a speed of 10 KM/HR. A starts from point X at 5:00 PM, B starts in the same direction at 5:15 PM. Will B catch up with A? If yes, at what time?
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Distance covered by A in 1 hr = 5Km
Thus
at 6 PM
A will be 5Km away from x
Distance Covered by B Starting at 5:15 Pm in 1 hour = 10 Km
So
in 1 hr ie at 6:15 Pm B will be 10 Km away from X
So he will be 5 Km away from X when the time is 5:45
Thus B will meet A at 5:45 PM
Thus
at 6 PM
A will be 5Km away from x
Distance Covered by B Starting at 5:15 Pm in 1 hour = 10 Km
So
in 1 hr ie at 6:15 Pm B will be 10 Km away from X
So he will be 5 Km away from X when the time is 5:45
Thus B will meet A at 5:45 PM
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Answer:
5:30 PM
Explanation:
A starts at 5pm from x.
A having speed 5kmph, will cover 2.5kms in 30mins.
B having speed 10kmph, will cover 2.5kms in 15 mins.
Therefore if A starts at 5 and B starts at 5.15 they will meet at 5.30.
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