Question

2. H(t)=√x²+2x+4;h(2)
3. k(x)= 3x²-1/2x+4;k (-3)
4. f(x)= 2x²+5x-9;f(5x-2)
5. g(p) = 4ˣ; x = 3 / 2

Answer 1

Answer:

l hope you understand from this solution

Answer 2

$2. Given \: h(t) = \sqrt{ x^{2} + 2x + 4 }$

$\red{ Value \: of \: h(2) } \\= \sqrt{ 2^{2} + 2 \times 2 + 4 } \\= \sqrt{4 + 4 + 4 }\\= \sqrt{ 12} \\= 2\sqrt{3}$

Therefore .,

$\red{ Value \: of \: h(2) }\green { = 2\sqrt{3}}$

$3. Given \: k(x) =3x^{2} - \frac{1}{2} x + 4$

$\red{ Value \: of \: k(-3) }\\= 3\times (-3)^{2} - \frac{1}{2} \times (-3) + 4 \\= 27 + \frac{3}{2} + 4 \\= 31 + \frac{3}{2}\\= \frac{ 62 + 3}{2} \\= \frac{65}{2}$

Therefore.,

$\red{ Value \: of \: k(-3) }\green { = \frac{65}{2}}$

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