Math, asked by ankit434488, 10 months ago

2) Harshan took a loan at a rate of simpleinterest 7% in the year with an increase of 0.25% in each subsequent year. He paid interest of Rs. 4425 after 4 years. How muchloan did he take?​

Answers

Answered by varungeorge2
5

Answer:

Step-by-step explanation:

total interest =rupees 4425,rate=7%

increasing by 0.25% everyear

let total loan amount=p

p=(4425*100)/(7*1+7.25*1+7.5*1+7.75*1)

=442500/29.5

= ruppes 15000

Answered by venupillai
7

Answer:

Loan taken by Harshan = Rs.15,000

Step-by-step explanation:

P = Principal = Loan taken by Harshan = ?

For the first year:

R = 7 per cent per year

T = 1 year

SI  = (P*R*T)/100 = (P*7*1)/100 = 0.07*P

For the second year:

R = 7.25 per cent per year ...(increase of 0.25% over the previous rate)

T = 1 year

SI  = (P*R*T)/100 = (P*7.25*1)/100 = 0.0725*P

For the third year:

R = 7.50 per cent per year ...(increase of 0.25% over the previous rate)

T = 1 year

SI  = (P*R*T)/100 = (P*7.50*1)/100 = 0.075*P

For the fourth year:

R = 7.75 per cent per year ...(increase of 0.25% over the previous rate)

T = 1 year

SI  = (P*R*T)/100 = (P*7.75*1)/100 = 0.0775*P

From the above equations, we get the total simple interest paid over the four-year period as:

0.07*P + 0.0725*P + 0.075*P + 0.0775*P

= (0.07 + 0.0725 + 0.075 + 0.0775) * P

= 0.295*P

We are given that the total simple interest paid = Rs.4425

=> 0.295*P = 4425

=> P = (4425/0.295)

=> P = 15000

The loan taken by Harshan = Rs.15,000

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