2.
Hind the values of the following
reasons for
and
give
stepe involved.
4 A
--
+198
CB3
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12A+6AB=A0912A+6AB=A09
Here, we can see that , A+B=9→(1)A+B=9→(1)
2+A=0→(2)2+A=0→(2)
1+6=A→(3)1+6=A→(3)
From (2), we can see that possible values for AA is 88 or 77.
For AA to be 77, A+BA+B should be greater that 99 that is not possible from (1)(1).
So, value of AA is 88.
From (1), we can see that if AA = 88, then B=9−8=1B=9-8=1
So, A=8andB=1A=8andB=1
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