Question

2 hockey players one with velocity 2 metre per second & weight 70 kg comes from west and tackle another player with weight 50 kg and velocity 4 metre per second coming from east
What will be the force of their collision

Answer 1

Answer:

Total momentum of two player

m

1

u

1

+m

2

u

2

=60(5)+55(−6)

=300−(330)

=−30Kgms

−1

Total momentum of two collision =(m

1

+m

2

)V

Conservation of momentum

-30=(m

1

+m

2

)V

V=

115

−30

V=−0.26ms

−1