2. Hold the spring balance (or tie it to the stand), suspended with the metal bob in air. Measure the weight of the bob. Let its weight be ‘WF'
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Answer:
Given,
Weight of the object in air =0.1N
Weight of the object in water =0.08N
The volume of the object (V)=?
The reduction in weight is due to buoyant force (F
B
).
∴ Buoyant force (0.1−0.08)=0.02N
From Archemede's principle,
F
B
=Weight of the displaced water = Volume of water displaced× Density of water×g
⇒0.02=V×10
3
×10
⇒V=
10
4
0.02
m
3
=0.02×
10
4
10
6
cm
3
=2cm
3
Explanation:
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