2. How many grams of sulphuric acid (H2SO4) will be required to completely react with 1.2 g of magnesium metal ? How much quantity of magnesium sulphate (MgSO4) will be formed in the reaction ? [Mg = 24; S = 32;0= 16; H = 1]
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Answer:
4.9 g H2SO4,
6g MgSO4.
Explanation:
H2SO4 + Mg ---→ MgSO4 + H2
↓ ↓ ↓ ↓
98 g 24g 120g 2g
with 24 g Mg H2SO4 reacts 98g
with 1 g Mg H2SO4 reacts 98/24 g
with 1.2 g Mg H2SO4 reacts 98×1.2/ 24 = 4.9 g H2SO4.
with 98 g H2SO4, 120 g MgSO4 reacts
with 1 g H2SO4, 120/98 g MgSO4 reacts
with 4.9 g H2SO4 120×4.9/98 = 6g MgSO4 reacts.
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