2. How many numbers are there between 100 and 1000 such that every digit is either
2 or 9 ?
3. How many 3-digit even positive numbers can be formed from the digits 0 to 9, if the
digits can be repeated.
Answers
Answered by
0
Answer:
Dude, I have the answer for the first question only.
Step-by-step explanation:
Just think in your mind that you have 3 boxes one for unit place one for tens place and one for hundred place. As we want the number between 100 and 1000 all are 3 digit no. except 1000 and we know it can be neglected.
so for unit place we have two choices either 2 or 9. same for tens place and hundred place. so the answer is 2×2×2=8
Sorry for answering only half
Hope it helpsssss:0
Answered by
0
Answer:
I think I can answer your question.
The answer for the first question is 8
The answer to the second question will be 450.
Step-by-step explanation:
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