2) How many of the three digit natural numbers are divisible by 5?
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A.P=100,105,110,………..,995
Therefore,a=100
d=5
a+(n-1)d=995
100+(n-1)(5)=995
(n-1)(5)=895
(n-1)=179
n=180
Therefore ,there are 180 three digit numbers which are divisible by 5
Therefore,a=100
d=5
a+(n-1)d=995
100+(n-1)(5)=995
(n-1)(5)=895
(n-1)=179
n=180
Therefore ,there are 180 three digit numbers which are divisible by 5
prajaktakuldharan:
hey can u explain me after this step (n-1)(5)=895
no need to explain i understand Thanks for this
Answered by
1
180 three digit numbers
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