Question

2 How much does r? - 2x + 5 exceeds 3r? – 5x + 6? + -2x2 + 3x - 1 O + 3x – 1 O 2x2 + 3x - 1 0-2r + 3x - 1

I NEED SERIOUS HELP IN THIS

Answer 1

Answer:

3x-+09)+4=33+-7q5=1509) mark me as brainly for more answers

Answer 2

Answer:

Option a : -2x^2+3x-1

Step-by-step explanation:

x square - 2 X + 5 - ( 3 x square - 5 x + 6 )

= x square - 2 X + 5 - 3 x square + 5 x-6

= -2 X square + 3 x- 1