Question

2.How much heat energy is necessary to raise the temperature of 150kg of water from 30 deg celsius to 100 deg celsius?​

Answer 1

Explanation:

We have 150kg of water at 18C and we want to raise the temperature to 50C.

We know that the energy required is:

ΔH = m•Cp•ΔT where m is mass, Cp is heat capacity and ΔT is temperature change.

Cp for water is 4.186kJ/kg

So, ΔH = 150(4.186)(50 – 18)

ΔH = 20,092.8kJ = 20.09MJ

20.09 megajoules sounds like a lot of energy, but think of it this way — if this is an electric heater, it is only 5.58kWh

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