Question

(2) How much heat energy is necessary to raise the temperature of 5 kg of water
from 20°C to 100°C.



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Answer 1

Answer is 400 J

Explanation:

Q = msdtheta

= 5 × 1 × (100 - 20)

= 400J

Answer 2

Answer: Quantity of heat required to raise 5 kg of water from 20 0C to 1000C is given by the formula:Q=m×c×ΔT(Q is usually used to symbolize that heat required in a case like this.) For water, the value of . C is 4.186Jg°C.So,Q=750×4.186×85=266858J=266.858kJDT = temperature difference =100-20=80 0C.

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