Question

-2+i/(1-2i)^2. Find the conjugate of the following

Answer 1

$(-2+i)/(1-2i)^{2} \\\\(-2+i)/(1+4i^{2}-4i)\\ \\(-2+i)/(1-4-4i)\\\\(-2+i)/(-3-4i)\\\\(-2+i)/(-1)(3+4i)\\\\(-1)(-2+i)/(3+4i)\\\\Rationalise\\\\(-1) (-2+i)(3-4i)/(3-4i)(3+4i)\\\\(-1)(-2+i)(3-4i)/(9-16i^{2})\\ \\(-1)(-2+i)(3-4i)/(9+16)\\\\(-1)(-6+8i+3i-4i^{2})/25\\\\(-1)(11i-6+4)/25\\\\(-1)(11i-2)/25\\\\(2-11i)/25\\z = 2/25 - 11i/25\\\\z = 2/25 + (-11i/25)\\\\conjugate$

ˉz = 2/25 - (-11i/25)

ˉz  = 2/25 + 11i/25