Question

(2+I) (2-3i) (4-3i)

Answer 1

(2+i)(2-3i)(4-3i)
(2+i)(2*4 -3i*4 - 2*3i -3i*-3i)
(2+i) (8 - 12i -6i +9i^2)
(2+i) (8 - 18i + 9(-1) ) we know that i^2 = -1

(2+i) ( -18i -1)

(2*-18i +i*-18i +2*-1 + i(-1))

(-36i -18i^2 -2 -i)

(-36i -18(-1) -2 -1)

(-36i +18 - 2 -1)

(-36i + 15)