Question

(2+i) (2-i) (1+i) = ​

Answer 1

Answer:

$(x + y)(x - y) = {x}^{2} - {y}^{2} \\ so \: \\ (2 + i)(2 - i)(1 + i) \\ = {2}^{2} - {i}^{2} (1 + i) \\ = {2}^{2} + {2i}^{2} - {i}^{2} - {i}^{3} \\ = {2}^{2} + {i}^{2} + {i}^{3}$

Answer 2

$\tt\huge\purple{hello!!!}$

HERE IS UR ANSWER

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$(2 + i)(2 - i)(1 + i) \\ ( {2}^{2} - {i}^{2} )(1 + i) \\ (4 - {i}^{2} )(1 + i) \\ 4 - {i}^{2} + 4i - {i}^{3} \\ 4 + 4i - {i}^{2} - {i}^{3}$