(2+i)/(3-i)(1+2i) find a&b
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(2+ i)/(3-i)(1 +2i) = a + ib
or, (2+i)/(3+6i -i -2i^2) = a +ib
or, (2+ i)/[3+5i-2(-1)] = a + ib [since, i^2 = -1]
or, (2+ i)/[3+5i+2] = a +ib
or, (2+ i)/(5+5i) = a +ib
or, (2+ i)(5-5i)/(5+5i)(5-5i) = a +ib [Conjugate multiplication]
or, (10-10i +5i-5i^2)/(25-25i^2) = a +ib
or, (10-5i +5)/(25 +25) = a +ib
or, (15-5i)/50 = a +ib
or, 5(3-i)/50 = a+ib
or, (3-i)/10=a+ib
Therefore, a = 3/10 and b = -1/10
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