Question

(2+i)/(3-i)(1+2i) value of a and b​

Answer 1

Answer:

i^2=-1 (constant value)

$\frac{2 + i}{(3 - i)(1 + 2i)}$

$\frac{(2 + i)}{3 + 6i - i - 2i {}^{2} }$

$\frac{2 + i}{3 + 5i - 2( - 1)}$

$\frac{2 + i}{5 + 5i}$

$\frac{2 + i}{5 + 5i} \times \frac{5 - 5i}{5 - 5i}$

$\frac{10 - 10 i - 5i - 5i {}^{2} }{25 - 25i {}^{2} }$

$\frac{10 - 15i + 5}{50}$

$\frac{15 - 15i}{50}$

$\frac{15(1 - i)}{50}$

$\frac{3 - 3i}{10}$

$\frac{3}{10} - \frac{3}{10} i = a + bi$

Answer 2

Ans is in the picture understand it