2. (i) Find the mean of first n natural numbers.
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Answer:
n(n+1)/2
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Answer:
a(first term) = 1
d(common difference) = 1
Sn = n/2 [ 2a + (n-1)d]
= n/2 [2+n-1]
= (2n + n^2 - n) / 2
= (n^2 + n) / 2
OR
Sn = n/2 (t1 + tn)
= n/2 (1 + n)
= (n + n^2) / 2
= (n^2 + n) / 2
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