2 + i is a root of x2 + ax+b=0
where a,b are real then (a,b)=
Answers
Answered by
0
Step-by-step explanation:
we have to put the values and we will get the answer of the equation
pls mark it as brillant
I will not be able to give the solution as my classes are going on
Answered by
0
P(X)=x
2
+ax+b a,b∈R
Roots are real
g(x)=p(x
3
)4
x
3
=t
g(x)=p(t)
p(t)=t
2
+at+b
Roots are real but t=x
3
Let t=β
x
3
=β
x=(β)
3
1
,(β
3
1
)w,(β
3
1
),w
2
Only 1 real root, 2−image.
Same are other roots
t=γ
It has only one real root
Total 2− distinct real roots and 4− Image.
hope it helps you
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