Question

(2+i)x^2-(5-i)x+2(1-i)=0​

Answer 1

Answer:

$2 {x}^{2} + i {x}^{2} - 5x + ix + 2 - 2i = 0 \\ 2 {x}^{2} - 5 x + 2 + i {x}^{2} + ix = 0 \\ 2 {x}^{2} - 4x - x + 2 + i( {x}^{2} + x) = 0 \\ 2x( x - 2) - 1(x - 2) = - i( {x}^{2} + x) \\ (2x + 1)(x - 2) = - i( {x}^{2} + x)$

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Step-by-step explanation:

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Answer 2

Answer:

sokution is attached. suoer imaginary Roots.