(2+i)x+(i-3)y=4 then (x,y)=?
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ANSWER:
Given:
- (2 + i)x + (i - 3)y = 4
To Find:
- Value of (x, y)
Solution:
We are given that,
⇒ (2 + i)x + (i - 3)y = 4
On opening the brackets,
⇒ 2x + ix + iy - 3y = 4
⇒ (2x - 3y) + (x + y)i = 4 + 0i
On comparing real terms,
⇒ 2x - 3y = 4 --------(1)
And, on comparing imaginary terms,
⇒ x + y = 0
Transposing y to RHS,
⇒ x = -y --------(2)
Putting (2) in (1),
⇒ 2x - 3y = 4
⇒ 2(-y) - 3y = 4
⇒ -2y - 3y = 4
⇒ -5y = 4
⇒ y = -4/5
So,
⇒ x = -y = -(-4/5) = 4/5
Hence, x is (4/5) and y is (-4/5).
Therefore, (x, y) = (4/5, -4/5*)
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