Question

2. সূত্রের সাহায্যে গুণ করি :
(i) (xy+pq)(xy-pq)
(iii) (2x-y+3z) (2x+y+3z)
(v) (a – 2) (a + 2) (a + 4)​

Answer 1

Answer:

1. (xy+pq)(xy-pq)

=(xy)^2-(pq)^2 [a^2-b^2=(a+b)(a-b)]

2. (2x-y+3z)(2x+y+3z)

={(2x+3z)-y}{(2x+3z)+y}

=(2x+3z)^2–y^2 [a^2-b^2= (a+b)(a-b)]

3. (a-2)(a+2)(a+4)

=(a^2-b^2) (a+4)

=a^3+4a^-b^2a-4b^2