Question

2 identical parallel plate capacitors connected to a battery with the switch 's' closed . the switch 's' is now open and the free space between the plate of the capacitor is filled with a dielectric of k=3. Find the ratio of total energy stored in both capacitors before and after the introduction of the dielectric

Answer 1

Let the capacitance of each capacitor be C. Total electrostatic energy stored in capacitors V1 = CE2 .............(i) Now dielectric in introduces after opening the switch S. Now capacitance of capacitor A is KC .'.Energy stored in A =1/2(KC)E2 =1/2KCE2 Let the charge stored in capacitor B initially be Q. In an open circuit, the charge will remain same. Read more on Sarthaks.com - https://www.sarthaks.com/179914/two-identical-parallel-plate-capacitors-connected-battery-volts-with-the-switch-closed...