Question

2. if 1 is zero of polynomial p(x)=ax^2-3(a-1)x-1 then find the value of a
(CBSE 2010-1M)​

Answer 1

Answer:

1

Step-by-step explanation:

If one 1 is zero of polynomial then it satisfies the equation

So,

ax^2 - 3(a-1)x -1 = 0

a(1)^2 - 3(a-1)1 -1 = 0

a - 3a + 3 -1 = 0

2 = 2a

a = 1

Hope this helps you

Answer 2

Answer:

a = 1

Step-by-step explanation:

ax²-3(a-1)-1 = 0

x = 1, a(1)²-3(0) -1 = 0

a-1 = 0

a = 1