Question

2. If 1 is zero of polynomial p(x)-ax® 3a-1)x-1 then find the value of a.
(CBSE 2010-1M)
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Answer 1

Answer: 1

Explanation:

p(x) = ax²- 3(a-1)x -1

Given, 1 is its zero

p(x) = a(1)² -3(a-1)1 -1 = 0

a - 3a+3 -1 = 0

-2a + 2 = 0

-2a = -2

a = -2/-2

a = 1