Question

2.) If 10g ice at. Zero degree celsios is mixed with water at 20 degree

Answer 1

Explanation:

Specific heat of water which is $ 1cal/gram{/^ \circ }_C $ . Hence according to the question, 10g of water at 20deg cel has 200 calories. But the requirement to melt $ 10g $ of ice would be $ 800cal $ , So at best the water would melt some of the ice and the mixture would remain at $ {0^ \circ }_C $