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If 2^(2x+3) +3^2 .2^x + 1 = 0 then values of x are
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2^(2x+3)-3^2.2^x+1=0
or, (2^2x)×(2^3)-9.2^x+1=0
or , 8×2^2x-9×2^x+1=0
or, 8×(2^x)^2–9×2^x+1=0
or, 8m^2–9m+1=0 ,asuming 2^x=m
or, 8m^2–8m-m+1=0
or, 8m(m-1)-1(m-1)=0
or, ( m-1)(8m-1)=0
or, m=1 or 1/8
when m=1 , 2^x=1=2^0 , x=0
when m=1/8, 2^x=1/8=1/2^3=2^(-3)
x= (-3)
x=0 or -3 ans
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